Wide Is Polynomial in Standard Form Then Classify It by Degree and Number of Terms Chapter 5 Review

Because of the form of a polynomial role, nosotros tin can run into an infinite variety in the number of terms and the power of the variable. Although the order of the terms in the polynomial function is not important for performing operations, nosotros typically arrange the terms in descending social club of power, or in full general form. The caste of the polynomial is the highest power of the variable that occurs in the polynomial; it is the power of the kickoff variable if the function is in full general form. The leading term is the term containing the highest power of the variable, or the term with the highest caste. The leading coefficient is the coefficient of the leading term.

A Full general Note: Terminology of Polynomial Functions

Diagram to show what the components of the leading term in a function are. The leading coefficient is a_n and the degree of the variable is the exponent in x^n. Both the leading coefficient and highest degree variable make up the leading term. So the function looks like f(x)=a_nx^n +…+a_2x^2+a_1x+a_0.

Figure 6

We oft rearrange polynomials so that the powers are descending.

When a polynomial is written in this mode, we say that it is in general grade.

How To: Given a polynomial function, identify the degree and leading coefficient.

  1. Find the highest power of ten
    to determine the degree part.
  2. Identify the term containing the highest power of x
    to observe the leading term.
  3. Identify the coefficient of the leading term.

Example 5: Identifying the Caste and Leading Coefficient of a Polynomial Part

Identify the caste, leading term, and leading coefficient of the post-obit polynomial functions.

[latex]\brainstorm{cases} f\left(x\right)=3+2{10}^{two}-4{x}^{3} \\ g\left(t\right)=5{t}^{5}-2{t}^{three}+7t\\ h\left(p\right)=6p-{p}^{3}-two\end{cases}\\[/latex]

Solution

For the function [latex]f\left(x\right)\\[/latex], the highest power of x is 3, so the degree is three. The leading term is the term containing that degree, [latex]-4{ten}^{3}\\[/latex]. The leading coefficient is the coefficient of that term, –4.

For the function [latex]1000\left(t\right)\\[/latex], the highest ability of t is 5, so the caste is 5. The leading term is the term containing that caste, [latex]five{t}^{5}\\[/latex]. The leading coefficient is the coefficient of that term, v.

For the part [latex]h\left(p\right)\\[/latex], the highest power of p is 3, and so the degree is 3. The leading term is the term containing that caste, [latex]-{p}^{3}\\[/latex]; the leading coefficient is the coefficient of that term, –one.

Endeavor It three

Identify the degree, leading term, and leading coefficient of the polynomial [latex]f\left(x\correct)=4{10}^{2}-{x}^{half dozen}+2x - 6\\[/latex].

Solution

Identifying Terminate Beliefs of Polynomial Functions

Knowing the degree of a polynomial function is useful in helping us predict its stop behavior. To determine its finish behavior, look at the leading term of the polynomial function. Because the power of the leading term is the highest, that term volition grow significantly faster than the other terms as 10 gets very large or very pocket-sized, so its behavior will dominate the graph. For whatsoever polynomial, the finish beliefs of the polynomial volition match the cease behavior of the term of highest degree.

Polynomial Office Leading Term Graph of Polynomial Function
[latex]f\left(x\right)=5{x}^{4}+2{x}^{3}-ten - 4\\[/latex] [latex]5{x}^{4}\\[/latex]
Graph of f(x)=5x^4+2x^3-x-4.
[latex]f\left(10\right)=-2{x}^{6}-{x}^{5}+3{x}^{4}+{x}^{iii}\\[/latex] [latex]-2{10}^{6}\\[/latex]
Graph of f(x)=-2x^6-x^5+3x^4+x^3.
[latex]f\left(x\right)=3{x}^{5}-4{x}^{iv}+2{x}^{ii}+1\\[/latex] [latex]three{x}^{5}\\[/latex]
Graph of f(x)=3x^5-4x^4+2x^2+1.
[latex]f\left(x\correct)=-6{x}^{iii}+seven{10}^{ii}+3x+1\\[/latex] [latex]-6{x}^{three}\\[/latex]
Graph of f(x)=-6x^3+7x^2+3x+1.

Instance 6: Identifying End Behavior and Degree of a Polynomial Office

Draw the end behavior and determine a possible degree of the polynomial function in Effigy vii.

Graph of an odd-degree polynomial.

Figure 7

Solution

As the input values x go very large, the output values [latex]f\left(x\correct)\\[/latex] increment without bound. As the input values 10 get very small, the output values [latex]f\left(ten\right)\\[/latex] decrease without bound. Nosotros can describe the end behavior symbolically by writing

[latex]\begin{cases}\text{equally } x\to -\infty , f\left(10\correct)\to -\infty \\ \text{as } x\to \infty , f\left(x\correct)\to \infty \terminate{cases}\\[/latex]

In words, nosotros could say that as x values approach infinity, the office values approach infinity, and every bit x values approach negative infinity, the function values approach negative infinity.

Nosotros can tell this graph has the shape of an odd caste power role that has not been reflected, and then the degree of the polynomial creating this graph must be odd and the leading coefficient must exist positive.

Try It iv

Describe the finish behavior, and determine a possible degree of the polynomial function in Figure 9.

Graph of an even-degree polynomial.

Effigy 9

Solution

Example 7: Identifying End Beliefs and Degree of a Polynomial Role

Given the office [latex]f\left(10\correct)=-3{x}^{2}\left(x - 1\right)\left(x+4\right)\\[/latex], express the function as a polynomial in general form, and make up one's mind the leading term, degree, and terminate beliefs of the office.

Solution

Obtain the general form by expanding the given expression for [latex]f\left(ten\correct)\\[/latex].

[latex]\begin{cases} f\left(x\right)=-3{x}^{2}\left(ten - 1\right)\left(x+4\right)\\ \hfill =-3{x}^{2}\left({x}^{ii}+3x - four\right)\\ \hfill=-iii{x}^{4}-9{x}^{three}+12{x}^{2}\stop{cases}\\[/latex]

The general course is [latex]f\left(10\right)=-3{x}^{4}-9{x}^{three}+12{ten}^{2}\\[/latex]. The leading term is [latex]-3{10}^{iv}\\[/latex]; therefore, the caste of the polynomial is 4. The degree is even (4) and the leading coefficient is negative (–3), so the end behavior is

[latex]\brainstorm{cases}\text{as } ten\to -\infty , f\left(x\right)\to -\infty \\ \text{equally } ten\to \infty , f\left(x\right)\to -\infty \cease{cases}\\[/latex]

Try It 5

Given the function [latex]f\left(x\correct)=0.2\left(x - 2\correct)\left(ten+1\right)\left(x - 5\right)\\[/latex], express the function as a polynomial in general form and determine the leading term, caste, and end behavior of the function.

Solution

Identifying Local Behavior of Polynomial Functions

In add-on to the stop beliefs of polynomial functions, we are also interested in what happens in the "middle" of the function. In particular, we are interested in locations where graph behavior changes. A turning point is a bespeak at which the function values modify from increasing to decreasing or decreasing to increasing.

Figure 10

We are also interested in the intercepts. Equally with all functions, the y-intercept is the signal at which the graph intersects the vertical axis. The signal corresponds to the coordinate pair in which the input value is cipher. Because a polynomial is a office, only one output value corresponds to each input value so there tin can be just one y-intercept [latex]\left(0,{a}_{0}\correct)\\[/latex]. The x-intercepts occur at the input values that stand for to an output value of nil. It is possible to have more than one ten-intercept.

A General Note: Intercepts and Turning Points of Polynomial Functions

A turning point of a graph is a point at which the graph changes management from increasing to decreasing or decreasing to increasing. The y-intercept is the point at which the part has an input value of zero. The x-intercepts are the points at which the output value is zero.

How To: Given a polynomial function, decide the intercepts.

  1. Determine the y-intercept by setting [latex]x=0\\[/latex] and finding the corresponding output value.
  2. Determine the ten-intercepts by solving for the input values that yield an output value of zero.

Example 8: Determining the Intercepts of a Polynomial Function

Given the polynomial function [latex]f\left(ten\correct)=\left(x - 2\right)\left(x+i\right)\left(x - four\right)\\[/latex], written in factored grade for your convenience, decide the y– andx-intercepts.

Solution

The y-intercept occurs when the input is cypher so substitute 0 for x.

[latex]\begin{cases}f\left(0\right)=\left(0 - ii\right)\left(0+1\right)\left(0 - four\correct)\hfill \\ \text{ }=\left(-2\right)\left(1\correct)\left(-4\right)\hfill \\ \text{ }=8\hfill \stop{cases}\\[/latex]

The y-intercept is (0, viii).

The x-intercepts occur when the output is zilch.

[latex]\begin{cases}\text{ }0=\left(x - 2\correct)\left(x+i\correct)\left(ten - 4\right)\hfill \\ ten - 2=0\hfill & \hfill & \text{or}\hfill & \hfill & x+1=0\hfill & \hfill & \text{or}\hfill & \hfill & x - 4=0\hfill \\ \text{ }10=2\hfill & \hfill & \text{or}\hfill & \hfill & \text{ }x=-1\hfill & \hfill & \text{or}\hfill & \hfill & 10=iv \end{cases}[/latex]

Thex-intercepts are [latex]\left(ii,0\correct),\left(-1,0\correct)\\[/latex], and [latex]\left(4,0\correct)\\[/latex].

We can meet these intercepts on the graph of the function shown in Effigy xi.

Graph of f(x)=(x-2)(x+1)(x-4), which labels all the intercepts.

Effigy 11

Instance 9: Determining the Intercepts of a Polynomial Function with Factoring

Given the polynomial function [latex]f\left(10\right)={x}^{4}-4{x}^{ii}-45\\[/latex], determine the y– andx-intercepts.

Solution

The y-intercept occurs when the input is zero.

[latex]\begin{cases} \\ f\left(0\right)={\left(0\correct)}^{4}-four{\left(0\correct)}^{two}-45\hfill \hfill \\ \text{ }=-45\hfill \end{cases}\\[/latex]

The y-intercept is [latex]\left(0,-45\right)\\[/latex].

The x-intercepts occur when the output is zero. To determine when the output is goose egg, we volition need to factor the polynomial.

[latex]\begin{cases}f\left(x\right)={x}^{4}-iv{ten}^{2}-45\hfill \\ =\left({ten}^{2}-ix\right)\left({x}^{2}+5\right)\hfill \\ =\left(ten - 3\right)\left(x+3\correct)\left({x}^{2}+5\right)\hfill \end{cases}[/latex]

[latex]0=\left(10 - 3\right)\left(x+3\right)\left({x}^{2}+5\right)\\[/latex]

[latex]\begin{cases}10 - 3=0\hfill & \text{or}\hfill & ten+iii=0\hfill & \text{or}\hfill & {x}^{2}+five=0\hfill \\ \text{ }x=iii\hfill & \text{or}\hfill & \text{ }10=-iii\hfill & \text{or}\hfill & \text{(no existent solution)}\hfill \terminate{cases}\\[/latex]

The 10-intercepts are [latex]\left(3,0\right)\\[/latex] and [latex]\left(-3,0\right)\\[/latex].

Nosotros can come across these intercepts on the graph of the function shown in Effigy 12. We can encounter that the function is fifty-fifty considering [latex]f\left(ten\correct)=f\left(-x\correct)\\[/latex].

Graph of f(x)=x^4-4x^2-45, which labels all the intercepts at (-3, 0), (3, 0), and (0, -45).

Figure 12

Try It half-dozen

Given the polynomial function [latex]f\left(x\right)=two{x}^{three}-6{x}^{two}-20x\\[/latex], determine the y– and x-intercepts.

Solution

Comparing Shine and Continuous Graphs

The caste of a polynomial function helps u.s.a. to determine the number of x-intercepts and the number of turning points. A polynomial function ofdue northth caste is the production of n factors, so it will have at well-nigh n roots or zeros, or x-intercepts. The graph of the polynomial role of degree due north must have at most n – 1 turning points. This means the graph has at well-nigh one fewer turning point than the caste of the polynomial or ane fewer than the number of factors.

A continuous function has no breaks in its graph: the graph tin can be drawn without lifting the pen from the paper. A shine curve is a graph that has no sharp corners. The turning points of a smoothen graph must always occur at rounded curves. The graphs of polynomial functions are both continuous and smooth.

A General Annotation: Intercepts and Turning Points of Polynomials

A polynomial of degree n will accept, at almost, nten-intercepts and n – i turning points.

Example 10: Determining the Number of Intercepts and Turning Points of a Polynomial

Without graphing the office, make up one's mind the local behavior of the role by finding the maximum number of 10-intercepts and turning points for [latex]f\left(x\right)=-3{x}^{x}+four{ten}^{7}-{10}^{4}+2{x}^{three}\\[/latex].

Solution

The polynomial has a degree of x, so there are at most due north10-intercepts and at about north – 1 turning points.

Try It vii

Without graphing the office, determine the maximum number of x-intercepts and turning points for [latex]f\left(10\right)=108 - 13{x}^{9}-8{x}^{4}+14{x}^{12}+2{x}^{3}\\[/latex]

Solution

Example 11: Cartoon Conclusions about a Polynomial Function from the Graph

What tin we conclude most the polynomial represented by the graph shown in the graph in Figure 13 based on its intercepts and turning points?

Graph of an even-degree polynomial.

Figure xiii

Solution

Graph of an even-degree polynomial that denotes the turning points and intercepts.

Figure 14

The end beliefs of the graph tells us this is the graph of an even-degree polynomial.

The graph has 2 10-intercepts, suggesting a degree of two or greater, and 3 turning points, suggesting a degree of 4 or greater. Based on this, it would exist reasonable to conclude that the degree is fifty-fifty and at to the lowest degree 4.

Effort It 8

What can we conclude about the polynomial represented by Effigy 15 based on its intercepts and turning points?

Graph of an odd-degree polynomial.

Effigy xv

Solution

Example 12: Drawing Conclusions about a Polynomial Function from the Factors

Given the function [latex]f\left(10\right)=-4x\left(x+3\right)\left(x - iv\right)\\[/latex], determine the local behavior.

Solution

The y-intercept is found by evaluating [latex]f\left(0\right)\\[/latex].

[latex]\begin{cases}f\left(0\right)=-iv\left(0\right)\left(0+3\right)\left(0 - iv\correct)\hfill \hfill \\ \text{ }=0\hfill \end{cases}\\[/latex]

The y-intercept is [latex]\left(0,0\right)\\[/latex].

The x-intercepts are found by determining the zeros of the function.

[latex]\brainstorm{cases}0=-4x\left(x+3\correct)\left(x - 4\right)\\ ten=0\hfill & \hfill & \text{or}\hfill & \hfill & x+three=0\hfill & \hfill & \text{or}\hfill & \hfill & ten - 4=0\hfill \\ x=0\hfill & \hfill & \text{or}\hfill & \hfill & \text{ }ten=-3\hfill & \hfill & \text{or}\hfill & \hfill & \text{ }x=4\end{cases}\\[/latex]

The x-intercepts are [latex]\left(0,0\correct),\left(-3,0\right)\\[/latex], and [latex]\left(four,0\right)\\[/latex].

The degree is 3 and then the graph has at most ii turning points.

Try It 9

Given the function [latex]f\left(ten\correct)=0.2\left(x - 2\right)\left(x+1\right)\left(ten - 5\right)\\[/latex], determine the local behavior.

Solution

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